One end of a helical spring is fixed while the other end carries the load W which moves with simple harmonic motion. The frequency of motion is given by (where $$\delta $$ = Deflection of the spring)
A
$$2\pi \sqrt {\frac{{\text{g}}}{\delta }} $$
B
$$\frac{1}{{2\pi }}\sqrt {\frac{{\text{g}}}{\delta }} $$
C
$$2\pi \sqrt {\frac{\delta }{{\text{g}}}} $$
D
$$\frac{1}{{2\pi }}\sqrt {\frac{\delta }{{\text{g}}}} $$
Correct Answer: $$\frac{1}{{2\pi }}\sqrt {\frac{{\text{g}}}{\delta }} $$