One end of a helical spring is fixed while the other end carries the load W which moves with simple harmonic motion. The frequency of motion is given by (where $$\delta $$ = Deflection of the spring.)

A $$2\pi \sqrt {\frac{g}{\delta }} $$
B $$\frac{1}{{2\pi }}\sqrt {\frac{g}{\delta }} $$
C $$2\pi \sqrt {\frac{\delta }{g}} $$
D $$\frac{1}{{2\pi }}\sqrt {\frac{\delta }{g}} $$

Correct Answer: $$\frac{1}{{2\pi }}\sqrt {\frac{g}{\delta }} $$

Bissoy MCQ
#Mechanical Engineering #Engineering Mechanics

Related Questions

One end of a helical spring is fixed while the other end carries the load W which moves with simple harmonic motion. The frequency of motion is given by (where $$\delta $$ = Deflection of the spring)
A $$2\pi \sqrt {\frac{{\text{g}}}{\delta }} $$
B $$\frac{1}{{2\pi }}\sqrt {\frac{{\text{g}}}{\delta }} $$
C $$2\pi \sqrt {\frac{\delta }{{\text{g}}}} $$
D $$\frac{1}{{2\pi }}\sqrt {\frac{\delta }{{\text{g}}}} $$
When a closely-coiled helical spring of mean diameter (D) is subjected to an axial load (W), the deflection of the spring ($$\delta $$) is given by (where d = Diameter of spring wire, n = No. of turns of the spring and C = Modulus of rigidity for the spring material)
A $$\frac{{{\text{W}}{{\text{D}}^3}{\text{n}}}}{{{\text{C}}{{\text{d}}^4}}}$$
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