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The population of a town is 4.2 × 106. If the population increases by 75 per 1000 per annum, then what will be the population after 2 years ?

The population of a town is 4.2 × 106. If the population increases by 75 per 1000 per annum, then what will be the population after 2 years ? Correct Answer 4853625

Percentage annual increase :
$$\eqalign{ & = \left( {\frac{{75}}{{1000}} \times 100} \right)\% \cr & = 7\frac{1}{2}\% \cr & = \frac{{15}}{2}\% \cr} $$
Population after 2 years :
$$\eqalign{ & = 4200000{\left( {1 + \frac{{15}}{{2 \times 100}}} \right)^2} \cr & = \left( {4200000 \times \frac{{43}}{{40}} \times \frac{{43}}{{40}}} \right) \cr & = 4853625 \cr} $$

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