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The population of a town increases at a rate of 8% per annum. If the population of the town after 3 years will be 80812, what is the population of the town 2 years ago?

The population of a town increases at a rate of 8% per annum. If the population of the town after 3 years will be 80812, what is the population of the town 2 years ago? Correct Answer 55000

If the current population is P and increasing at a rate of R% per annum, the population n years ago is given as,

Population n years ago = P/

Given, population after 3 years, P = 80812

Rate of increase, R = 8%

n = 3 + 2 = 5 years

∴ 2 years ago, Population of the town = 80812/

⇒ 80812/

⇒ 80812/1.4693

⇒ 55000

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