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The integrating factor for differential equation $$\frac{{{\text{dP}}}}{{{\text{dt}}}} + {{\text{k}}_2}{\text{P}} = {{\text{k}}_1}{{\text{L}}_0}{{\text{e}}^{ - {{\text{k}}_1}{\text{t}}}}$$     is

The integrating factor for differential equation $$\frac{{{\text{dP}}}}{{{\text{dt}}}} + {{\text{k}}_2}{\text{P}} = {{\text{k}}_1}{{\text{L}}_0}{{\text{e}}^{ - {{\text{k}}_1}{\text{t}}}}$$     is Correct Answer e<sup>k<sub>2</sub>t</sup>

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