Related Questions

The bending moment at a section tends to bend or deflect the beam and the internal stresses resist its bending. The resistance offered by the internal stresses, to the bending, is called
A Compressive stress
B Shear stress
C Bending stress
D Elastic modulus
In a simple bending theory, one of the assumptions is that the plane sections before bending remain plane after bending. This assumption means that
A Stress is uniform throughout the beam
B Strain is uniform throughout the beam
C Stress is proportional to the distance from the neutral axis
D Strain is proportional to the distance from the neutral axis
If W is total load per unit area on a panel, D is the diameter of the column head, L is the span in two directions, then the sum of the maximum positive bending moment and average of the negative bending moment for the design of the span of a square flat slab, should not be less than
A $$\frac{{{\text{WL}}}}{{12}}{\left( {{\text{L}} - \frac{{2{\text{D}}}}{3}} \right)^2}$$
B $$\frac{{{\text{WL}}}}{{10}}{\left( {{\text{L}} + \frac{{2{\text{D}}}}{3}} \right)^2}$$
C $$\frac{{{\text{WL}}}}{{10}}{\left( {{\text{L}} - \frac{{2{\text{D}}}}{3}} \right)^2}$$
D $$\frac{{{\text{WL}}}}{{12}}{\left( {{\text{L}} - \frac{{\text{D}}}{3}} \right)^2}$$
The operation of bending a sheet of metal along a curved axis, is known as
A Plunging
B Notching
C Slitting
D Forming
Federation Cup, World Cup, Allywy International Trophy and Challenge Cup are awarded to winners of -
A Tennis
B Basketball
C Volleyball
D Cricket
The operation of cutting of a flat sheet to the desired shape is called
A Shearing
B Piercing
C Punching
D Blanking
Springback in sheet metal bending depends on the
A Elastic limit
B Bend radius
C Degree of bend
D Thickness of sheet
A shaft is subjected to bending moment M and a torque T simultaneously. The ratio of the maximum bending stress to maximum shear stress developed in the shaft, is
A $$\frac{{\text{M}}}{{\text{T}}}$$
B $$\frac{{\text{T}}}{{\text{M}}}$$
C $$\frac{{2{\text{M}}}}{{\text{T}}}$$
D $$\frac{{2{\text{T}}}}{{\text{M}}}$$
The bending moment ‘M’ and a torque ‘T’ is applied on a solid circular shaft. If the maximum bending stress equals to maximum shear stress developed, then ‘M’ is equal to
A $$\frac{{\text{T}}}{2}$$
B 1T
C 2T
D 4T
A shaft of diameter D is subjected to a twisting moment (T) and a bending moment (M). If the maximum bending stress is equal to maximum shear stress developed, then M is equal to
A $$\frac{{\text{T}}}{2}$$
B T
C 2T
D 4T

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