Related Questions

The valve rod in a steam engine is connected to an eccentric rod by
A Cotter joint
B Bolted joint
C Knuckle joint
D Universal coupling
In a steam engine, the valve rod is connected to an eccentric rod by means of
A Cotter joint
B Knuckle joint
C Universal joint
D Flange coupling
Which of the following cotter joint will be used to connect strap end of a connecting rod?
A Spigot and socket cotter joint
B Sleeve and cotter joint
C Gib and cotter joint
D Any one of these
The strap end of a connecting rod of steam engine is joined by
A Gib of cotter joint
B Sleeve and cotter joint
C Spigot socket cotter joint
D Knuckle joint
Mass moment of inertia of a thin rod about its one end is ___________ the mass moment of inertia of the same rod about its mid-point
A Same as
B Twice
C Thrice
D Four times
In a glass tube type water indicator for a boiler, one end of the tube is connected to water space and the other end is connected to
A Water space also
B Chimney
C Steam space
D Superheater
At a college football game, 4/5 of the seats in the lower deck of the stadium were sold. If one-fourth of all the seating in the stadium is located in the lower deck, and if 2/3 of all the seats in the stadium were sold, what fraction of the unsold seats in the stadium were in the lower deck?
A 3/20
B 1/6
C 1/3
D 7/15
At a college football game, 4/5 of the seats in the lower deck of the stadium were sold. If one-fourth of all the seats in the stadium were located in the lower deck, and if 2/3 of all the seats in the stadium were sold, what fraction of the unsold seats in the stadium were in the lower deck?
A 3/20
B 1/6
C 1/3
D 7/15
At a collegae football game, 4/5 of the seats in the lower deck of the stadium were sold. If one-forth of all the seating in the stadium is located in the lower deck and if 2/3 of all the seats in the stadium were sold. What fraction of the unsold seats in the stadium were in the lower deck?
A 3/20
B 1/6
C 1/3
D 7/15
The primary unbalanced force due to inertia of reciprocating parts in a reciprocating engine is given by (where m = Mass of reciprocating parts, $$\omega $$ = Angular speed of crank, r = Radius of crank, $$\theta $$ = Angle of inclination of crank with the line of stroke and n = Ratio of the length of connecting rod to radius of crank)
A $${\text{m}}{\omega ^2}{\text{r}}\sin \theta $$
B $${\text{m}}{\omega ^2}{\text{r}}\cos \theta $$
C $${\text{m}}{\omega ^2}{\text{r}}\frac{{\sin 2\theta }}{{\text{n}}}$$
D $${\text{m}}{\omega ^2}{\text{r}}\frac{{\cos2\theta }}{{\text{n}}}$$

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