The maximum diameter of the hole that can be punched from a plate of maximum shear stress $${\frac{1}{4}^{{\text{th}}}}$$ of its maximum crushing stress of punch, is equal to (where t = Thickness of the plate)

The maximum diameter of the hole that can be punched from a plate of maximum shear stress $${\frac{1}{4}^{{\text{th}}}}$$ of its maximum crushing stress of punch, is equal to (where t = Thickness of the plate) Correct Answer 4t

Related Questions

When a hole of diameter ‘d’ is punched in a metal of thickness 't', then the force required to punch a hole is equal to (where $${\tau _{\text{u}}}$$ = Ultimate shear strength of the material of the plate)
A plate with an elliptical hole in the centre, with semi-major axis (a) perpendicular to the direction of loading and semi-minor axis (b) along the direction of loading, is subjected to a pull P. The maximum stress induced at the edge of the hole is equal to (where $$\sigma $$ = Stress for a plate with no hole i.e. nominal stress)