A man bought a horse and a cart. If he sold the horse at 10 % loss and the cart at 20 % gain, he would not lose anything; but if he sold the horse at 5% loss and the cart at 5% gain, he would lose Rs. 10 in the bargain. The amount paid by him was Rs._______ for the horse and Rs.________ for the cart.

A man bought a horse and a cart. If he sold the horse at 10 % loss and the cart at 20 % gain, he would not lose anything; but if he sold the horse at 5% loss and the cart at 5% gain, he would lose Rs. 10 in the bargain. The amount paid by him was Rs._______ for the horse and Rs.________ for the cart. Correct Answer 400, 200

Let X be the cost of horse and Y be the cost of the cart.10% of loss in selling horse = 20% of gain in selling the cart.Therefore, $$\frac{{10}}{{100}} \times {\text{X}}$$ = (20 × 100) × YOr, X = 2y --------------(1)5% of loss in selling horse is 10 more than the 5% gain in selling the cart.Therefore, $$\frac{5}{{100}} \times {\text{X}} - 10 = \frac{5}{{100}} \times {\text{Y}}$$=> 5X – 1000 = 5YUsing equation (1),=> 10Y – 1000 = 5Y=> 5Y = 1000=> Y =200=> X = 400CP of Horse = Rs. 400CP of the Cart = Rs. 200