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A population of variety of tiny bush in an experiment field increased by 10% in the first year, increased by 8% in the second year but decreased by 10% in third year. If the present number of bushes in the experiment field is 26730, then the number of variety of bushes in beginning was:

A population of variety of tiny bush in an experiment field increased by 10% in the first year, increased by 8% in the second year but decreased by 10% in third year. If the present number of bushes in the experiment field is 26730, then the number of variety of bushes in beginning was: Correct Answer 25000

Let the number of bushes originally be 100Number of bushes after one year100 ==10% (↑) ==> 110After second year it becomes110 ==8%(↑) ==> 118.8After third year,118.8 ==8%(↓)==> 109.3Now, according to the question109.3 = 267301 = $$\frac{{26730}}{{109.3}}$$So, 100 = $$\frac{{26730}}{{109.3}} \times 100$$    = 25000
Thus, number of bushes originally was 25000NOTE:You can take number of bushes originally as x then solve for the x

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