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EcoRI restriction sites on a 10kb DNA fragment are shown below
Upon partial digestion, what are the lengths (in kb) of all the possible DNA fragments obtained?

EcoRI restriction sites on a 10kb DNA fragment are shown below
Upon partial digestion, what are the lengths (in kb) of all the possible DNA fragments obtained? Correct Answer 2, 3, 4, 5, 6, 7, 8, and 10

Related Questions

"A complete restriction digestion of a circular plasmid (5000bp) was carried out with HindIII, BamHI and EcoRI individually. Restriction digestion yielded following fragments.
Plasmid + HindIII → 1200bp and 3800bp
Plasmid + BamHI → 5000bp
Plasmid + EcoRI → 2500bp
The number of sites for EcoRI, BamHI and HindIII present on this plasmid are"
A linear DNA fragment is 100% labeled at one end and has 3 restriction sites for EcoRI. If it is partially digested by EcoRI so that all possible fragments are produced, how many of these fragments will be labeled and how many will not be labeled?
Two restriction enzymes A and B have eight and four base pairs as their recognition sites respectively. The ratio of the number of fragments that they will generate on restriction digestion of a genomic DNA of E.coli is approximately
Analysis of a hexapeptide using enzymatic cleavage reveals the following result:
• Amino acid composition of the peptide is: 2R, A, V, S, Y
• Trypsin digestion yields two fragments and the compositions are: (R, A, V) and (R, S, Y)
• Chymotrypsin digestion yields two fragments and the compositions are: (A, R, V, Y) and (R, S)
• Digestion with carboxypeptidase A yields no cleavage product.
Given: Trypsin cleaves at carboxyl side of R. Chymotrypsin cleaves at carboxyl side of Y. Carboxypeptidase A cleaves at amino side of the C-terminal amino acid (except R and K) of the peptide.
The correct amino acid sequence of the peptide is:
If u (x, y, z, t) = f(x + iβy - vt) + g(x - iβy - vt), where f and g are arbitrary and twice differentiable functions, is a solution of the wave equation $$\frac{{\partial {u^2}}}{{\partial {x^2}}} = \frac{{{\partial ^2}u}}{{\partial {y^2}}} = \frac{1}{{{c^2}}}\frac{{{\partial ^2}u}}{{\partial {t^2}}}$$     then β is
Amplified fragment length polymorphism (AFLP)
P. A PCR-based tool
Q. Uses restriction enzymes to cut genomic DNA
R. Involves ligation of adaptors to the sticky ends of the restriction fragments
S. Involves amplification using primers complementary to the adaptor
Which one of the combinations of the following statements is true about antibody structure?
P. Limited proteolysis of rabbit IgG with the enzyme pepsin generates two antigen-binding regions (Fab) and an Fc fragment.
Q. Limited proteolysis of rabbit IgG with the enzyme papain generates a single bivalent antigen-binding region F(ab')2 and peptide fragments.
R. The Fc fragment of IgG can self-associate and crystallize into a lattice.
S. The F(ab')2 fragment of IgG is composed of both light and heavy chains.
The combined mixture of all labeled DNA fragments is electrophoresed to _____ the fragments by______ and the ladder of fragments is scanned for the presence of each of the four labels.
DNA ligase can ligate restriction site ends produced by EcoRI to the ends of DNA insert cut by the same enzyme.
Consider the following statements regarding chain elongation during DNA synthesis and choose the correct answer:
1. The separated strands are kept open by DNA binding proteins (DBPs)
2. A DNA chain is initiated on the 3'- OH end of the primer
3. Okazaki fragments are synthesized on one strand; there is continuous DNA synthesis in the other strand
4. Okazaki fragments are joined by endonuclease