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DNA ligase can ligate restriction site ends produced by EcoRI to the ends of DNA insert cut by the same enzyme.

DNA ligase can ligate restriction site ends produced by EcoRI to the ends of DNA insert cut by the same enzyme. Correct Answer True

EcoRI generates protruding 5’ ends (sticky ends) that are complementary to each other. Thus the ends are capable of reannealing with each other. Thus when both vector the same enzyme and DNA insert are cut using same cutter the strands anneal themselves but leaves two nicks in both the strands. Thus treatment with the enzyme ligase seals the nicks using ATP.

Related Questions

"A complete restriction digestion of a circular plasmid (5000bp) was carried out with HindIII, BamHI and EcoRI individually. Restriction digestion yielded following fragments.
Plasmid + HindIII → 1200bp and 3800bp
Plasmid + BamHI → 5000bp
Plasmid + EcoRI → 2500bp
The number of sites for EcoRI, BamHI and HindIII present on this plasmid are"
Consider the following statements.
I. T4 DNA ligase can catalyze blunt end Ligation more efficiently than E. coli DNA ligase.
II. The ligation efficiency of T4 DNA Ligase can be increased with PEG and ficoll.
A linear DNA fragment is 100% labeled at one end and has 3 restriction sites for EcoRI. If it is partially digested by EcoRI so that all possible fragments are produced, how many of these fragments will be labeled and how many will not be labeled?
Consider the following statements and choose the correct answer:
In order to be a useful vector, a plasmid:
1. Must possess the genes essential for replication of DNA
2. Must carry, at least, one gene that can be used as a marker for the selection of the plasmid in the transformed cell
3. Must include, at least, one gene recognizable by its product or activity, which possesses within it a cutting site for a restriction enzyme
4. In the rep region must contain a cutting site for the restriction enzyme to be used
Mechanism of ligation for both T4 DNA ligase and E. coli DNA ligase makes use of Adenosine Monophosphate (AMP). Which of the steps is involved in the ligation mechanism?
EcoRI restriction sites on a 10kb DNA fragment are shown below
Upon partial digestion, what are the lengths (in kb) of all the possible DNA fragments obtained?
Steps given are to draw an involute of a given square ABCD. Arrange the steps. i. With B as centre and radius BP1 (BA+ AD) draw an arc to cut the line CB-produced at P2. ii. The curve thus obtained is the involute of the square. iii. With centre A and radius AD, draw an arc to cut the line BA-produced at a point P1. iv. Similarly, with centres C and D and radii CP2 and DP3 respectively, draw arcs to cut DC-produced at P3 and AD-produced at P4.
Consider the following statements regarding DNA replication and choose the correct answer:
1. The very first requirement of DNA synthesis is the presence of a template or plan along which the new strand is to be constructed
2. The second requirement is of a DNA-dependent-DNA polymerase or simply DNA polymerase enzyme
3. A DNA Pol cannot join two free nucleotides; one of them must be anchored by hydrogen bonds to a DNA strand
4. Replication takes place bidirectionally
Amplified fragment length polymorphism (AFLP)
P. A PCR-based tool
Q. Uses restriction enzymes to cut genomic DNA
R. Involves ligation of adaptors to the sticky ends of the restriction fragments
S. Involves amplification using primers complementary to the adaptor
In the case of deletion of a restriction site, it should be cleaved with the same restriction enzyme.