If the ratio of long and short spans of a two way slab with corners held down is r, the actual reduction of B.M. is given by
A
$$\frac{5}{6}\left( {\frac{{\text{r}}}{{1 + {{\text{r}}^2}}}} \right){\text{M}}$$
B
$$\frac{5}{6}\left( {\frac{{{{\text{r}}^2}}}{{1 + {{\text{r}}^2}}}} \right){\text{M}}$$
C
$$\frac{5}{6}\left( {\frac{{{{\text{r}}^2}}}{{1 + {{\text{r}}^3}}}} \right){\text{M}}$$
D
$$\frac{5}{6}\left( {\frac{{{{\text{r}}^2}}}{{1 + {{\text{r}}^4}}}} \right){\text{M}}$$
Correct Answer: $$\frac{5}{6}\left( {\frac{{{{\text{r}}^2}}}{{1 + {{\text{r}}^4}}}} \right){\text{M}}$$
