Raju got married 8years ago. His present age is 6/5 times his age at the time of his marriage Raju's sister was 10years younger to him at the time of hismarriage. The present age of Raju's sister is ?

Two boys are playing on a ground. Both the boys are less than 10 years old. Age of the younger boy is equal to the cube root of the product of the age of the two boys. If we place the digit representing the age of the younger boy to the left of the digit representing the age of the elder boy, we get the age of the father of the younger boy. Similarly, we place the digit representing the age of the elder boy to the left of the digit representing the age of the younger boy and divide the figure by 2, we get the age of the mother of the younger boy. The mother of the younger boy is younger than his father by 3 years. Then, what are the ages of elder and younger boys ?

A

E = 15 & Y = 3

B

E = 14 & Y = 12

C

E = 40 & Y = 22

D

E = 4 & Y = 2

Given below are quantities named A,B and C. Based on the given information, you have to determine the relation between the quantities. You should use the given data and your knowledge of mathematics to choose among the possible answer. Akash’s present age is six years less than Badshah’s age after nine years. The ratio of present age of Badshahand RAFTAAR is 5:9. Raftaar is 21 years younger than Denny and Denny is three years older than Honey. Square of the Honey’s present age is 1350 more than 15 times of Honey’s present age? Quantity A: What is the difference between AKASH’s present age and HONEY’s age after 16 years? Quantity B: After 6 years Mankirat’s age is twice that of Akash’s present age. Diljeet’s present age is 3.5 times of 25% of sum of present age of Mankirat and A. What is the present age of Diljeet? Quantity C: Twice of A’s present age is eight years more than that of Babbu’spresent age, then find the Babbu’s present age?

A

<,>

B

>,<

C

=,<

D

=,>

E

>,>

Ramiya got married 8 years ago. Her present age is 6/5 times her age at the time of her marriage. Ramiya’s brother was 10 years younger than her at the time of her marriage. What is the ratio of Ramiya’s present age and her brother’s age at the time of her marriage?

A

2 : 7

B

7 : 9

C

4 : 7

D

8 : 5

E

None of the above

Rajan got married 8 years ago. His present age is $$\frac{6}{5}$$ times his age at the time of his marriage. Rajan's sister was 10 years younger to him at the time of his marrige. The age of Rajan's sister is = ?

A

32 years

B

36 years

C

38 years

D

40 years

Rajesh got married 7 years ago. His present age is 8/7 times of his age at the time of marriage. At the time of his marriage, his brother was 5 years younger to him. What will be the age of his brother after 10 years?

A

58 years

B

45 years

C

55 years

D

61 years

E

57 years

Given below are two quantities named 1 and 2. Based on the given information, you have to determine the relation between the two quantities. You should use the given data and your knowledge of Mathematics to choose between the possible answers. Quantity 1: How many years ago were Brad and Angelina married? The ratio of the age of Brad and Angelina is 4 : 3. At the time of marriage the ratio was 5 : 3 and After 4 years this ratio will become 9 : 7. Quantity 2: The present age of the younger son. The younger son is 3 years younger than the elder one. 10 years ago, the father was twice of his elder son and the difference of their present ages is 15 years.

A

Quantity 1 ≥ Quantity 2

B

Quantity 1 ≤ Quantity 2

C

Quantity 1 < Quantity 2

D

Quantity 1 > Quantity 2

E

Quantity 1 = Quantity 2 or No relation

Ghanshyam and Raju got their marks(out of 50 marks) in 4 subjects i.e English, Science, Maths and Social. The avg marks obtained by Raju is 38. The ratio of marks obtained by Raju and Ghanshyam in Maths is 5 ∶ 6 and the average marks obtained by Ghanshyam is 41. If the marks scored by both of them in English and Science is same and in Social Raju got 5 marks less than Ghanshyam. What is the marks scored by them in English and Science if Raju scored 40 marks in Social?

A

42

B

36.5

C

38.5

D

40

E

32.5

Father is aged 3times more than his son Ronit. After 8years, he would be two and a half times of Roni's age. After further 8years,how many times would he be of Ronit's age?

A

2times

B

2.5times

C

3.5times

D

3times

What is the age of Teja? A: Four years ago, Raju was as old as Teja is at present. B: Sitas present age is two times of Rajus present age. C: The average age of Teja and Sita is 19 years.

A

Any two statements are sufficient to give answer

B

Only C is sufficient

C

All of three statements are necessary to give answer

D

Even using all the three statements answer cannot be found

Simplify the value of $$\frac{{{\text{0}}{\text{.9}} \times {\text{0}}{\text{.9}} \times {\text{0}}{\text{.9 + 0}}{\text{.2}} \times {\text{0}}{\text{.2}} \times {\text{0}}{\text{.2 + 0}}{\text{.3}} \times {\text{0}}{\text{.3}} \times {\text{0}}{\text{.3}} - {\text{3}} \times 0.9 \times {\text{0}}{\text{.2}} \times {\text{0}}{\text{.3}}}}{{{\text{0}}{\text{.9}} \times {\text{0}}{\text{.9 + 0}}{\text{.2}} \times {\text{0}}{\text{.2 + 0}}{\text{.3}} \times {\text{0}}{\text{.3}} - 0.9 \times {\text{0}}{\text{.2}} - {\text{0}}{\text{.2}} \times {\text{0}}{\text{.3}} - 0.3 \times 0.9}} = ?$$

A

1.4

B

0.054

C

0.8

D

1.0

Raju got married 8years ago. His present age is 6/5 times his age at the time of his marriage Raju's sister was 10years younger to him at the time of hismarriage. The present age of Raju's sister is ?

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