A bag contains 600 coins of 25 p denomination and 1200 coins of 50 p denomination. If 12% of 25 p coins and 24% of 50 p coins are removed, the percentage of money removed from the bag is nearly :

A bag contains 600 coins of 25 p denomination and 1200 coins of 50 p denomination. If 12% of 25 p coins and 24% of 50 p coins are removed, the percentage of money removed from the bag is nearly : Correct Answer 21.6 %

Total money = Rs.[600*(25/100)+1200*(50/100)]= Rs. 750.

 

25 paise coins removed = Rs. (600*12/100) = 72.

 

50 paise coins removed = Rs. (1200*24/100)= 288.

 

Money removed =Rs.(72*25/100+288*50/100)  = Rs.162.

 

Required percentage = (162/750*100)% = 21.6 %.

Related Questions

A primary class mathematics teacher poses the following question to his students: "Reena and Sharma went to a shop to buy a bag. There were many bags with different price tags. They got confused by looking at so many price tags. Can you help them by arranging the price tags either in ascending or descending order"? BAG-A\(\rightarrow\) Rs. 4732, BAG B \(\rightarrow\) Rs. 2364,  BAG- C \(\rightarrow\) Rs. 1934, BAG- D \(\rightarrow\) Rs. 3475, BAG- E \(\rightarrow\) Rs. 2937, BAG-F \(\rightarrow\) Rs. 3004. In the given context, which of the following statements is true?