Find the square root of 4a2 + 9b2 + c2 + 12ab – 6bc – 4ac.
Find the square root of 4a2 + 9b2 + c2 + 12ab – 6bc – 4ac. Correct Answer 2a + 3b – c
We know that, (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca. 4a2 + 9b2 + c2 + 12ab – 6bc – 4ac = (2a)2 + (3b)2 + (-c)2 + 2(2a)(3b) + 2(3b)(-c) + 2(2a)(-c) = (2a + 3b – c)2 Therefore, square root of (2a + 3b – c)2 is 2a + 3b – c
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Feb 20, 2025