Find the inertia force of reciprocating parts of an engine, given mass of the reciprocating parts 200 kg and acceleration of reciprocating parts is 120 m/s2.

Find the inertia force of reciprocating parts of an engine, given mass of the reciprocating parts 200 kg and acceleration of reciprocating parts is 120 m/s2. Correct Answer 24000 kg-m/s2

FI = MR * AR = 200 * 120 = 24000 kg-m/s2

Related Questions

The primary unbalanced force due to inertia of reciprocating parts in a reciprocating engine is given by (where m = Mass of reciprocating parts, $$\omega $$ = Angular speed of crank, r = Radius of crank, $$\theta $$ = Angle of inclination of crank with the line of stroke and n = Ratio of the length of connecting rod to radius of crank)
The secondary unbalanced force due to inertia of reciprocating parts in a reciprocating engine is given by (where m = Mass of reciprocating parts, $$\omega $$ = Angular speed of crank, r = Radius of crank, $$\theta $$ = Angle of inclination of crank with the line of stroke and n = Ratio of the length of connecting rod to radius of crank)