A V-belt operates at 25 m/s peripheral speed. The mass of the belt per unit length is 0.9 kg/m. The value of centrifugal tension in belt is ______

A V-belt operates at 23.56 m/s peripheral speed. The mass of the belt per unit length is 0.9 kg/m. The value of centrifugal tension is _______

A

514 N

B

523 N

C

500 N

D

599 N

বন্ধুর ঘনত্বের ক্ষেত্রে: i. বায়ুর ঘনত্ব 1.29 kgm-3ii. হাইড্রোজেন গ্যাসের ঘনত্ব বায়ুর ঘনত্বের চেয়ে কমiii. সঞ্চয়ী কোষে ব্যবহৃত সালফিউরিক এসিডের ঘনত্ব 1.5 × 103 kgm-3 থেকে 1.3 × 103 kgm-3 নিচের কোনটি সঠিক?

A

i ও ii

B

i ও iii

C

ii ও iii

D

i, ii ও iii

"It is now expected that the variable production cost per unit and the selling price per unit will each increase by 10%, and fixed production cost will rise by 25%. What will be the new break even point?
Selling price - Rs 6 per unit
Variable production cost - Rs 1.20 per unit
Variable selling cost - Rs 0.40 per unit
Fixed production cost - Rs 4 per unit
Fixed selling cost - Rs 0.80 per unit
Budgeted production and sales for the year are 10,000 units."

A

8,788 units

B

11,600 units

C

11,885 units

D

12,397 units

When the belt is transmitting maximum power, the belt speed should be (Where, m = mass of belt per meter (kg/m) and Pmax = maximum permissible tension in belt (N))

A

$$\sqrt {\frac{{{\text{P}}\max }}{{2{\text{m}}}}} $$

B

$$\sqrt {\frac{{{\text{P}}\max }}{{3{\text{m}}}}} $$

C

$$\sqrt {\frac{{{\text{P}}\max }}{{\text{m}}}} $$

D

$$\sqrt {\frac{{{\text{3m}}}}{{{\text{P}}\max }}} $$

When the belt is transmitting maximum power, the belt speed should be
(Where, m = mass of belt per meter (kg/m) and Pmax = maximum permissible tension in belt (N))

A

$$\sqrt {\frac{{{\text{P}}\max }}{{2{\text{m}}}}} $$

B

$$\sqrt {\frac{{{\text{P}}\max }}{{3{\text{m}}}}} $$

C

$$\sqrt {\frac{{{\text{P}}\max }}{{\text{m}}}} $$

D

$$\sqrt {\frac{{{\text{3m}}}}{{{\text{P}}\max }}} $$

What is the distance covered by boat N upstream in 5 hours? Which of the following option is sufficient alone to find the answer? A) Boat M is travelling downstream with 20% more downstream speed of boat N. Speed of boat M in still water is 10% more than the speed of boat N in still water. B) Boat M and Boat N are travelling downstream with speed 33 km/hr and 40 km/hr respectively and speed of boat M is still water is 2 times the speed of stream. C) Speed of boat M in still water is 6 km/hr less then speed of boat N in still water and speed of stream is 10 km/hr. D) Speed of stream is ½ times the speed of boat N in still water and downstream speed of boat M is 44 km/hr. E) Speed of stream is 10 km/hr and ratio of upstream speed of boat M and boat N is 3 : 2 respectively.

A

Only A and B

B

Only B and C

C

Only B

D

All A, B, C and D

E

None of A, B, C and D

From an alloy, two specimens are machined and tested separately under tension and compression. The engineering stress-strain curves as well as the true stress-true strain curves for tension and compression are plotted in the same diagram. Identify the correct statements:
P. The engineering stress-strain curves in tension and compression are identical.
Q. The true stress-true strain curve in compression is lower than the true stresstrue strain curve in tension due to Bauschinger effect.
R. The true stress-true strain curve in tension is above the corresponding engineering stress-strain, curve.
S. The true stress-true strain curve in tension and compression are identical.

A

P, Q

B

Q, R

C

Q, S

D

R, S

If P₁ and P₂ are the tight and slack side tensions in the belt, then the initial tension P_i (neglecting centrifugal tension) will be equal to (Where, P_c is centrifugal tension)

A

$${{\text{P}}_1} - {{\text{P}}_2}$$

B

$${{\text{P}}_1} + {{\text{P}}_2}$$

C

$$\frac{1}{2}\left( {{{\text{P}}_1} + {{\text{P}}_2}} \right)$$

D

$$\frac{1}{2}\left( {{{\text{P}}_1} + {{\text{P}}_2}} \right) + {{\text{P}}_{\text{c}}}$$

The ratio of belt tensions $$\frac{{{{\text{p}}_1}}}{{{{\text{p}}_2}}}$$ considering centrifugal force in flat belt is given by where,
m = mass of belt per meter (kg/m)
v = belt velocity (m/s)
f = coefficient of friction
$$\alpha $$ = angle of wrap (radians)

A

$$\frac{{{{\text{p}}_1} - {\text{m}}{{\text{v}}^2}}}{{{{\text{p}}_2} - {\text{m}}{{\text{v}}^2}}} = {{\text{e}}^{{\text{f}}\alpha }}$$

B

$$\frac{{{{\text{p}}_1}}}{{{{\text{p}}_2}}} = {{\text{e}}^{{\text{f}}\alpha }}$$

C

$$\frac{{{{\text{p}}_1}}}{{{{\text{p}}_2}}} = {{\text{e}}^{ - {\text{f}}\alpha }}$$

D

$$\frac{{{{\text{p}}_1} - {\text{m}}{{\text{v}}^2}}}{{{{\text{p}}_2} - {\text{m}}{{\text{v}}^2}}} = {{\text{e}}^{ - {\text{f}}\alpha }}$$

A lady wants to buy the following items in the given price range- 1. Tomato between Rs. 40 and Rs. 45 per kg. 2. Grapes in the price range of Rs. 80 and Rs. 90 per kg. 3. Milk packets at Rs. 23 per liter. In which shop from the following will she definitely get all her items/ A. Shop S sells tomato at Rs. 22.5 per half kg, Grapes at Rs. 82 per kg and milk at Rs. 24 per liter. B. Shop H sells grapes at Rs. 21 per quarter kg, milk at 12.5 per half litre and tomato at Rs. 22 per half kg. C. Shop O sells milk at Rs. 11.5 per half litre, tomato at 21 per half kg and grapes at Rs. 43 per half kg. D. Shop P sells tomato at Rs. 23.5 per half kg, grapes at Rs. 85 per kg and milk at Rs. 23 per litre.

A

B

D

C

B

D

C

A V-belt operates at 25 m/s peripheral speed. The mass of the belt per unit length is 0.9 kg/m. The value of centrifugal tension in belt is ______

Related Questions