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A counter shaft of engineering workshop is being driven by electric motor with the help of canvas belt and pulley arrangement such that the speed of belt is 600 m/min and it transmits 50 KW. What will be the difference between tensions on either side of the belt?

A counter shaft of engineering workshop is being driven by electric motor with the help of canvas belt and pulley arrangement such that the speed of belt is 600 m/min and it transmits 50 KW. What will be the difference between tensions on either side of the belt? Correct Answer 5000

V = 600*10/60 = 10 m/s P = (T1-T2) * V 50000 = (T1-T2) * 10 T1 – T2 = 5000

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