The growth of S.cerevisiae on glucose under anaerobic conditions can be described by the following reaction: C6H12O6 + aNH3 → 0.59 CH1.64N0.16O0.52 (biomass) + 0.43 C3H8O3 + 1.54CO2 + 1.3C2H5OH + 0.036H2O and determine the product yield coefficient Y etoh/s and determine coefficient a.
The growth of S.cerevisiae on glucose under anaerobic conditions can be described by the following reaction: C6H12O6 + aNH3 → 0.59 CH1.64N0.16O0.52 (biomass) + 0.43 C3H8O3 + 1.54CO2 + 1.3C2H5OH + 0.036H2O and determine the product yield coefficient Y etoh/s and determine coefficient a. Correct Answer 0.33 g. g⁻¹, 0.094
Yetoh/s = 1.3 x MW EtOH / 1x MW glucose = 0.59 x 46/ 1×180 = 0.33 g.g⁻¹ N in NH3 = N in biomass (CH1.64N0.16O0.52) ∴ a = (0.59)(0.16) = 0.094.
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Feb 20, 2025