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What is the specific energy of a satellite in circular orbit of radius 7078 km around earth? Given, gravitational parameter of earth is 398,600 km3/s2.

What is the specific energy of a satellite in circular orbit of radius 7078 km around earth? Given, gravitational parameter of earth is 398,600 km3/s2. Correct Answer -28.16 km2/s2

Specific energy = -μ/(2r) = -398,600/(2*7078) = -28.1577 km2/s2

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