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Find the crack growth per cycle for a steel plate where the crack growth equation is given by: -> da/dN = A(ΔK)p The value of p=3, A= 6.9*10-18, and stress intensity factor variation is 1 kPa m1/2.

Find the crack growth per cycle for a steel plate where the crack growth equation is given by: -> da/dN = A(ΔK)p The value of p=3, A= 6.9*10-18, and stress intensity factor variation is 1 kPa m1/2. Correct Answer 6.9 nm/cycle

The crack growth is given as follows: -> da/dN = A (ΔK)p -> da/dN = 6.9*10-18 * (1*103)3 -> 6.9*10-9 da/dN = 6.9*10-9 m/cycle So the crack growth per cycle is 6.9 nm.

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