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The young’s modulus of the steel is 600 MPa, and the plastic stress required to extend the crack is 50*10-9, and the initial crack length is 2 microns. Find the fracture stress required to crack the material?

The young’s modulus of the steel is 600 MPa, and the plastic stress required to extend the crack is 50*10-9, and the initial crack length is 2 microns. Find the fracture stress required to crack the material? Correct Answer 15 MPa

The fracture stress according to Orowan’s theory of brittle fracture is (Eϒp/a)1/2 So; (600*106 * 50*10-9)/2*10-6 -> 15*106 -> 15 MPa.

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