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The transfer constant to the solvent for polymerization of of styrene in toluene at 60ᵒC is 0.125*10-5. How much dilution is required to decrease the molecular weight by 4 times when 1/Xn0 is 3.5*10-4?

The transfer constant to the solvent for polymerization of of styrene in toluene at 60ᵒC is 0.125*10-5. How much dilution is required to decrease the molecular weight by 4 times when 1/Xn0 is 3.5*10-4? Correct Answer 84

To decrease molecular weight by 4 times, 1/Xn becomes 4/Xn0, 4/Xn0 = 1/Xn0 + CI / Substituting the values, / = 84. Thus, dilution factor is 84.

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