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In the hydrodealkylation of toluene to benzene, the following reactions occur:
C7H8 + H2 → C6H6 + CH4
2C6H6 ⇋ C12H10 + H2
Toluene and hydrogen are fed to a reactor in a molar ratio 1 : 5.80% of the toluene gets converted and the selectivity of benzene (defined as moles of benzene formed/moles of toluene converted) is 90%. The fractional conversion of hydrogen is

In the hydrodealkylation of toluene to benzene, the following reactions occur:
C7H8 + H2 → C6H6 + CH4
2C6H6 ⇋ C12H10 + H2
Toluene and hydrogen are fed to a reactor in a molar ratio 1 : 5.80% of the toluene gets converted and the selectivity of benzene (defined as moles of benzene formed/moles of toluene converted) is 90%. The fractional conversion of hydrogen is Correct Answer 0.144

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The fresh feed to an ammonia synthesis reactor contains nitrogen, hydrogen and 2.0 mole per cent inerts. The molar ratio of H2:N2 is 3:1. The product stream consists of pure ammonia. Since conversion in the reactor is only 15%, a recycle stream is used and in order to avoid build-up of inerts, a purge stream is withdrawn. The rate of purge stream is adjusted to keep inert concentration in the recycle stream at 8 mole per cent. For a fresh feed rate of 100 moles/hr. Note that recycle stream contains only nitrogen, hydrogen and inerts. The N2:H2 ratio of 1:3 is maintained in every process stream, and calculate the moles of nitrogen entering the reactor and in the recycle stream?
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