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The molecular weight of the polymer, when styrene is polymerized at 60ᵒC, is halved by diluting it with ethyl benzene. What is the value of transfer constant to the solvent, if the dilution factor is 7 and the term 1/Xn0 is 4.8*10-4?

The molecular weight of the polymer, when styrene is polymerized at 60ᵒC, is halved by diluting it with ethyl benzene. What is the value of transfer constant to the solvent, if the dilution factor is 7 and the term 1/Xn0 is 4.8*10-4? Correct Answer 0.68

We have the expression for solvent transfer, 1/Xn = 1/Xn0 + CI / When molecular weight is halved, 1/Xn becomes 2/Xn0, then substituting the values and /= 7, we get CI as 0.68.

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