What is the formula of logarithmic mean temperature in terms of By-pass factor? b) Tm = td2 – td1 / log10 c) Tm = td2 – td1 / loge d) Tm = td2

The bypass factor (B. P. F.) in case of sensible heating of air is (Where td₁ = Dry bulb temperature of air entering the heating coil, td₂ = Dry bulb temperature of air leaving the heating coil, and td₃ = Dry bulb temperature of heating coil)

A

(td₂ - td₃)/(td₃ - td₁)

B

(td₃ - td₂)/(td₃ - td₁)

C

(td₃ - td₁)/(td₂ - td₃)

D

(td₃ - td₁)/(td₃ - td₂)

The bypass factor, in case of sensible cooling of air, is given by (where td₁ = Dry bulb temperature of air entering the cooling coil, td₂ = Dry bulb temperature of air leaving the cooling coil, and td₃ = Dry bulb temperature of the cooling coil)

A

(td₁ -td₃)/( td₂ -td₃)

B

(td₂ -td₃)/( td₁ -td₃)

C

(td₃ -td₁)/( td₂ -td₃)

D

(td₃ -td₂)/( td₁ -td₃)

What is the By-pass factor for heating coil, if td1 = temperature at entry, td2 = temperature at exit and td3 = coil temperature?

A

td3 – td1 / td3 – td1

B

td3 – td2 / td3 – td1

C

td3 – td2 / td2 – td1

D

td3 – td2 / td1 – td2

What is the By-pass factor for cooling coil, if td1 = temperature at entry, td2 = temperature at exit and td3 = coil temperature?

A

td3 – td1 / td3 – td1

B

td3 – td2 / td3 – td1

C

td3 – td2 / td2 – td1

D

td2 – td3 / td1 – td3

What is the contact factor for cooling coil, if td1 = temperature at entry, td2 = temperature at exit and td3 = coil temperature?

A

td1 – td2 / td1 – td3

B

td2 – td1 / td3 – td1

C

td3 – td2 / td2 – td1

D

td3 – td2 / td1 – td2

Which of the following is the correct equation? log10 b) E = Eo + log10 c) E = Eo – log10 d) E = Eo/ log10

A

E = Eo log10

B

(2.303RT)/nF

C

(2.303RT)/nF

D

(2.303RT)/nF

For given conditions, td1 = 288 K, td2 = 301 K and td3 = 314 K, the value of by-pass factor and contact factor is equal.

A

True

B

False

What is the By-pass factor for heating coil, if td1 = 19°C, td2 = 25°C and td3 = 37°C?

A

0.75

B

0.4

C

0.7

D

0.1

What is the By-pass factor for cooling coil, if td1 = 49°C, td2 = 36°C and td3 = 30°C?

A

0.315

B

0.31

C

0.320

D

0.3

What is the contact factor for heating coil, if td1 = 11°C, td2 = 32°C and td3 = 47°C?

A

0.5833

B

0.4833

C

0.7833

D

0.1833

What is the formula of logarithmic mean temperature in terms of By-pass factor? b) Tm = td2 – td1 / log10 c) Tm = td2 – td1 / loge d) Tm = td2 – td3 / loge

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