The angular velocity of the pinion is 40 rad/s and that of the gear is 12 rad/s. The path of recess is equal to 16 mm. Find the velocity of sliding at the end of the contact.

The angular velocity of the pinion is 40 rad/s and that of the gear is 12 rad/s. The path of recess is equal to 16 mm. Find the velocity of sliding at the end of the contact. Correct Answer 832 mm/s

ωp= 40 rad/s and ωg= 12 rad/s. Path of recess = 16 mm. Velocity of sliding = (ωp + ωg) x Path of recess = (40 + 12) x 16 = 832 mm/s.
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When the addenda on pinion and wheel is such that the path of approach and path of recess are half of their maximum possible values, then the length of the path of contact is given by (where r = Pitch circle radius of pinion, R = Pitch circle radius of wheel and $$\varphi $$ = Pressure angle)