The angular velocity of the pinion is 25 rad/s and that of the gear is 10 rad/s. The path of approach is equal to 15 mm. Find the velocity of sliding at the beginning of contact.

The angular velocity of the pinion is 25 rad/s and that of the gear is 10 rad/s. The path of approach is equal to 15 mm. Find the velocity of sliding at the beginning of contact. Correct Answer 525 mm/s

ωp= 25 rad/s and ωg= 10 rad/s. Path of approach = 15 mm. Velocity of sliding = (ωp + ωg) x Path of approach = (25 + 10) x 15 = 525 mm/s.
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