For the given figure, the brake can sustain a torque of 350 N-m and coefficient of friction between the band and drum is 0.3, If the drum rotates in anticlockwise direction, find force in N.

For the given figure, the brake can sustain a torque of 350 N-m and coefficient of friction between the band and drum is 0.3, If the drum rotates in anticlockwise direction, find force in N. Correct Answer 804

2.3 log(T1/T2) = μ.θ = 0.3×3.93 = 1.179 log(T1/T2) = 1.129/2.3 = 0.51 T1/T2 = 3.255 Braking torque = (T1-T2)r T1-T2 = 2000 therefore T1 = 2887N T2 = 887N Px500 = T1x150 – T2x35 P = 804N.
Bissoy MCQ

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In a band and block brake, the ratio of tensions on the tight and slack sides of band is given by (where $$\mu $$ = Coefficient of friction between the blocks and the drum, $$\theta $$ = Semi-angle of each block subtending at the centre of drum and n = Number of blocks)
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