For the given figure, the brake can sustain a torque of 350 N-m and coefficient of friction between the band and drum is 0.3, find necessary force required for clockwise rotation of the drum in N.

For the given figure, the brake can sustain a torque of 350 N-m and coefficient of friction between the band and drum is 0.3, find necessary force required for clockwise rotation of the drum in N. Correct Answer 64

2.3 log(T1/T2) = μ.θ = 0.3×3.93 = 1.179 log(T1/T2) = 1.129/2.3 = 0.51 T1/T2 = 3.255 Braking torque = (T1-T2)r T1-T2 = 2000 therefore T1 = 2887N T2 = 887N Px500 = T2x150 – T1x35 P = 64N.
Bissoy MCQ

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In a band and block brake, the ratio of tensions on the tight and slack sides of band is given by (where $$\mu $$ = Coefficient of friction between the blocks and the drum, $$\theta $$ = Semi-angle of each block subtending at the centre of drum and n = Number of blocks)
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