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Calculate the amount of air required for the following details. Flow: 300 m3/h BOD load: 800 mg/L

Calculate the amount of air required for the following details. Flow: 300 m3/h BOD load: 800 mg/L Correct Answer 700m3/hr

BOD load in Kg/day = Inlet BOD in mg/l x Flow in m3/day /1000 =800 x 300 / 1000=240 Kg/day. Theoretical oxygen requirement = BOD load x Kg of O2/Kg of BOD= 240 x 1.8 = 432 Kg of O2/day. Standard O2 Requirement = Theoretical O2 requirement/ Alpha x x Theta(Tww-20°C)/ Css= 432/24/ x 1.024(30-20)]/9.86=38.29 Kg of O2/hr. Air requirement = Actual Oxygen requirement/ (Density of air x % of O2 in air by weight x SOTE%) = 38.29 /( 1.201 x 0.232 x 0.1599)= 696 m3/hr. (Rounded off to 700 m3/hr). Factors assumed: SOTE=17.27%; Alpha=0.7; Beta=0.95; Theta=1.024; Surface saturation C=7.97 (Calculated); Site basin saturation Csw=8.64 (Calculated); Standard basin saturation Css=9.86 (Calculated).

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