A brass bar, having cross sectional area of 100mm2, is subjected to axial force of 50kN. The length of two sections is 100mm and 200mm respectively. What will be the total elongation of bar if E = 1.05 x 105 N/mm2 ?

A brass bar, having cross sectional area of 100mm2, is subjected to axial force of 50kN. The length of two sections is 100mm and 200mm respectively. What will be the total elongation of bar if E = 1.05 x 105 N/mm2 ? Correct Answer 1.428mm

Elongation in section 1 = P/AE x L = 50,000/(100×1.05×100,000) x 100 = 0.476mm Elongation In section 2 = P/AE x L = 50,000/(100×1.05×100,000) x 200 = 0.952mm Total elongation = 0.476 + 0.952 = 1.428mm.
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