A round bar made of same material consists of 4 parts each of 100mm length having diameters of 40mm, 50mm, 60mm and 70mm, respectively. If the bar is subjected to an axial load of 10kN, what will be the total elongation of the bar in mm?

A round bar made of same material consists of 4 parts each of 100mm length having diameters of 40mm, 50mm, 60mm and 70mm, respectively. If the bar is subjected to an axial load of 10kN, what will be the total elongation of the bar in mm? Correct Answer 40/πE ( 1/16 + 1/25 + 1/36 + 1/49)

Total elongation = 4PL/πE ( 1/d12 + 1/d22 + 1/d32 + 1/d42) = 4x10x100/πEx100 ( 1/16 + 1/25 + 1/36 + 1/49) mm = 40/πE ( 1/16 + 1/25 + 1/36 + 1/49).
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