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What will be the correction for three level sections, if the areas of 3 different sides, which are having unit distance are 121.31 sq. m, 145.76 sq. m, 176.65 sq. m and 45.87 sq. m, 45.67 sq. m, 72.43 sq. m?

What will be the correction for three level sections, if the areas of 3 different sides, which are having unit distance are 121.31 sq. m, 145.76 sq. m, 176.65 sq. m and 45.87 sq. m, 45.67 sq. m, 72.43 sq. m? Correct Answer -25.96

The formula of correction for three level section can be given as Cp = d*(h-hꞌ)*(w-wꞌ+w1-w1ꞌ) / 12. On substitution, we get Cp = 1*(121.31-45.87)*(145.76-45.67 +176.65-72.43) / 12 Cp = -25.96.

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