In the circuit shown below, the switch is closed at t = 0, applied voltage is v (t) = 50cos (102t+π/4), resistance R = 10Ω and capacitance C = 1µF. The complete solution of ‘i’ is? exp⁡(-t/0.00001)+4.99×10-3) cos⁡(100t+π/2+89.94o) b) i = exp⁡(-t/0.00001)+4.99×10-3) cos⁡(100t+π/2+89.94o) c) i = exp⁡(-t/0.00001)-4.99×10-3) cos⁡(100t+π/2+89.94o) d) i = exp⁡(-t/0.00001)-4.99×10-3) cos⁡(100t+π/2+89.94o)

In the circuit shown below, the switch is closed at t = 0, applied voltage is v (t) = 50cos (102t+π/4), resistance R = 10Ω and capacitance C = 1µF. The complete solution of ‘i’ is? exp⁡(-t/0.00001)+4.99×10-3) cos⁡(100t+π/2+89.94o) b) i = exp⁡(-t/0.00001)+4.99×10-3) cos⁡(100t+π/2+89.94o) c) i = exp⁡(-t/0.00001)-4.99×10-3) cos⁡(100t+π/2+89.94o) d) i = exp⁡(-t/0.00001)-4.99×10-3) cos⁡(100t+π/2+89.94o) Correct Answer i = exp⁡(-t/0.00001)+4.99×10-3) cos⁡(100t+π/2+89.94o)

The complete solution for the current is the sum of the complementary function and the particular integral. So, i = exp⁡(-t/0.00001)+4.99×10-3) cos⁡(100t+π/2+89.94o).

Related Questions

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