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In the following circuit, the value of Norton’s resistance between terminals a and b are ___________

In the following circuit, the value of Norton’s resistance between terminals a and b are ___________ Correct Answer RN = 90 Ω

By writing loop equations for the circuit, we get, VS = VX, IS = IX VS = 600(I1 – I2) + 300(I1 – I2) + 900 I1 = (600+300+900) I1 – 600I2 – 300I3 = 1800I1 – 600I2 – 300I3 I1 = IS, I2 = 0.3 VS I3 = 3IS + 0.2VS VS = 1800IS – 600(0.01VS) – 300(3IS + 0.01VS) = 1800IS – 6VS – 900IS – 3VS 10VS = 900IS For Voltage, VS = RN IS + VOC Here VOC = 0 So, Resistance RN = 90Ω.

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