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Given VDD = 25V, VP = -3V. When VGS = -3V, IDS = 10mA. Find the operating point of the circuit.

Given VDD = 25V, VP = -3V. When VGS = -3V, IDS = 10mA. Find the operating point of the circuit. Correct Answer -2.345V, 0.469mA

When VGS = VP then IDSS = IDS = 10mA Also, in above circuit, VGS = -IDSRS = – IDSx5k Thus, IDS = IDSS(1-VGS/VP)2 Solving we get, IDS = 0.766mA, 0.469mA Thus we get VGS = -3.83V, -2.345V However, VGS should lie between 0 and VP.

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