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If Av, Ai and Ap represents the voltage gain, current gain and power gain ratio of an amplifier which of the below is not the correct expression for the corresponding values in decibel?
A certain inverting amplifier has a closed-loop voltage gain of 25. The OP-amp has an open-loop voltage gain of 100,000. If an OP-amp with an open-loop voltage gain of 200,000 is substituted in the arrangement, the closed-loop gain
The ratio of the short circuit current gain of a current amplifier (Ai) to the open circuit voltage gain of a voltage amplifier (AV), given that both amplifiers have the same value of the input resistance (Ri) and output resistance (R0), is
You are given two amplifiers, A and B, to connect in cascade between a 10-mV, 100-kΩ source (S) and a 100-Ω load (L). The amplifiers have voltage gain, input resistance, and output resistance as follows: for A, 100 V/V, 10 kΩ, 10 kΩ, respectively; for B, 1 V/V, 100 kΩ, 100 Ω, respectively. Your problem is to decide how the amplifiers should be connected so that the voltage gain is maximum.
Below stated are some of the statements about the Alternating current. You need to identify which of the following is incorrect, 1. DC power is far more powerful than AC power. The efficiency and power to size characteristics of DC motors and apparatuses are increased. Lighting by DC (LED) is 75% more efficient than lighting from incandescence. 2. A comparatively high voltage alternating current may be generated and easily raised and dropped by the static equipment known as the transformer, which makes electrical energy transmission and distribution economical, 3. Initial costs and maintenance of the AC motor are less expensive since it has no switch and is less powerful than the DC motor for constant working speed, hence it is desired to create power as alternating current. 4. The great efficiency of transmission in ac makes electric power generation cost-effective, Produced in huge quantities in one station and distributed throughout a vast area.
When an electric current coil of a wattmeter is connected to the electric current path R and the voltage coil is connected between the electric current R path and the neutral side of the balanced three phase supply, it shows 10 kW. The line voltage along the phase sequence RYB is 400 V. The current drawn by the current path is 54 A. What is the new reading of the wattmeter if the voltage coil is connected between the lines B and the Y paths, even if the electric current coil is continuously present in the line R?
The voltage gain of the amplifier is 8 and the current gain is 7. The power gain of the amplifier is
If the output power of an amplifier is 10 V, and the input power supplied to the amplifier is 0.229 V given that the DC voltage used is 38.5 V, efficiency of the power amplifier is:
Consider a voltage series feedback network, where amplifier gain = 100, feedback factor = 5. For the basic amplifier, input voltage = 4V, input current=2mA. Find the input resistance of the network.
An amplifier without feedback has a voltage gain of 50, input resistance of 1 kΩ & Output resistance of 2.5 kΩ.The input resistance of the current shunt negative feedback amplifier using the above amplifier with a feedback factor of 0.2 is