Bissoy.com
Doctors Medicines MCQs Q&A

The mass and the radius of a planet are twice that of earth. Then, period of oscillation of a second pendulum on that planet will be ___________

The mass and the radius of a planet are twice that of earth. Then, period of oscillation of a second pendulum on that planet will be ___________ Correct Answer 2√2s

On earth, g=GM/R2 On planet, g‘=G2M/(4R)2 = g/2 T‘/T=√(g/g‘) = √((g/g)/2) = √2 T‘=√2×T=2√2 s.

Related Questions

If the 'Mercury planet' is called 'Uranus planet', 'Uranus planet' is called 'Jupiter planet', 'Jupiter planet' is called 'Mars planet', 'Mars planet' is called 'Earth planet', 'Earth planet' is called 'Saturn planet', 'Saturn planet' is called 'Venus planet', and 'Venus planet' is called 'Pluto planet', then on which planet do we live?
If the amplitude or oscillation of a simple pendulum is very small, then its time period of oscillation
1. depends on the length of the pendulum, L.
2. depends on the acceleration due to gravity, g.
3. depends upon the mass of the bob of the pendulum, m.
4. does not depend upon the amplitude of the pendulum, A.
Select the correct answer:
Which one of the following is the correct sequence of various stages of operating cycle of a manufacturing company?  1. Raw material conversion period, work-in-progress conversion period, Finished goods conversion period, Receivables conversion period 2. Raw material conversion period, work-in-progress conversion period, Creditors payment period, Receivables conversion period 3. Creditor payment period. Raw material conversion period, Receivables conversion period, work-in- progress conversion period 4. Raw material conversion period, Finished goods conversion period, work-in- progress conversion period. Receivables conversion period 
Consider the following statements.
A Simple Pendulum is set into oscillation. Then,
1. the acceleration is zero when the bob passes through the mean position.
2. in each cycle the bob attains a given velocity twice.
3. both acceleration and velocity of the bob are zero when it reaches its extreme position during the oscillation.
4. the amplitude of oscillation of the simple pendulum decreases with time.
Which of these statements are correct?
A pendulum clock is lifted to a height where the gravitational acceleration has a certain value of g. Another pendulum clock of same length, but of double the mass of the bob is lifted to another height where the gravitational acceleration is $$\frac{g}{2}$$. The time period of the second pendulum would be (in terms of period T of the first pendulum)
Consider the following the statements 1. The oscillation of a particle with fundamental frequency under the influence of restoring force is defined as forced oscillations 2. The oscillation of a body whose amplitude goes on decreasing with time is defined as damped oscillation. 3. The oscillation in which a body oscillates under the influence of an external periodic force is known as forced oscillation. Which of the following statements is/are correct?
Consider a planet whose mass and radius are both twice the mass and radius of Earth. The acceleration due to gravity on the surface of the planet is 'n' times that on Earth. The value of n is:
Suppose there is a planet whose mass and radius are twice the mass and radius of the Earth. The acceleration due to gravity on the surface of that planet is n times that of Earth. What will be the value of n:
The time period of a pendulum on earth is 2 seconds. What will be the time period of the same pendulum on a planet having acceleration due to gravity 9 times of earth?
The time period of a simple pendulum on the surface of the earth is “T”. What will be the time period of the same pendulum at a height of 2 times the radius of the earth?