Bissoy.com
Doctors Medicines MCQs Q&A

The time period of a simple pendulum on the surface of the earth is “T”. What will be the time period of the same pendulum at a height of 2 times the radius of the earth?

The time period of a simple pendulum on the surface of the earth is “T”. What will be the time period of the same pendulum at a height of 2 times the radius of the earth? Correct Answer 3T

Time period of the simple pendulum on the surface of the earth; T = (2 x pi) x (l / g)1/2 l = Length of the simple pendulum The time period of the simple pendulum at a certain height above the earth’s surface; T’ = (2 x pi) x (l / g’)1/2 g’ = Acceleration due to gravity at a certain height above the surface of the earth g’ for a height of 2R (R = Radius of the earth); g’ = (G*M1)/(R + 2R)2 = (G*M1)/(3R)2 = (1/9) x g T’ = (2 x pi) x (l / (1/9)g) ½ = 3 x = 3T.

Related Questions

“What is the different between height and radius of solid cylinder?” Which of the following option is sufficient alone to find the answer? A) A solid cylinder is made by melting a solid sphere. The radius of cylinder is 3 times the radius of a circle whose area is 154 sq.m. Height of cylinder is equal to the height of cone whose volume is 2772 cubic meters. B) Area of a rectangle whose longer side is ¾ times the radius of a solid cylinder, is 168 sq.m and, Volume of solid cylinder is 2772 cubic meters and its height is 18 m. C) A metallic cone of radius 15m and height 35m is melted into the solid cylinder of radius equal to the radius of a circle whose area is equal to the area of rectangle whose sides are in the ratio 4 : 3 respectively. D) The curved surface area of the solid cylinder is 3 time the surface area of a sphere of radius 7m and height of cylinder is equal to the height of a metallic cone whose curved surface area is 308 sq.m. 
Simplify the value of $$\frac{{{\text{0}}{\text{.9}} \times {\text{0}}{\text{.9}} \times {\text{0}}{\text{.9 + 0}}{\text{.2}} \times {\text{0}}{\text{.2}} \times {\text{0}}{\text{.2 + 0}}{\text{.3}} \times {\text{0}}{\text{.3}} \times {\text{0}}{\text{.3}} - {\text{3}} \times 0.9 \times {\text{0}}{\text{.2}} \times {\text{0}}{\text{.3}}}}{{{\text{0}}{\text{.9}} \times {\text{0}}{\text{.9 + 0}}{\text{.2}} \times {\text{0}}{\text{.2 + 0}}{\text{.3}} \times {\text{0}}{\text{.3}} - 0.9 \times {\text{0}}{\text{.2}} - {\text{0}}{\text{.2}} \times {\text{0}}{\text{.3}} - 0.3 \times 0.9}} = ?$$
$$\frac{{38 \times 38 \times 38 + 34 \times 34 \times 34 + 28 \times 28 \times 28 - 38 \times 34 \times 84}}{{38 \times 38 + 34 \times 34 + 28 \times 28 - 38 \times 34 - 34 \times 28 - 38 \times 28}}$$            is equal to = ?
A pendulum clock is lifted to a height where the gravitational acceleration has a certain value of g. Another pendulum clock of same length, but of double the mass of the bob is lifted to another height where the gravitational acceleration is $$\frac{g}{2}$$. The time period of the second pendulum would be (in terms of period T of the first pendulum)
Which one of the following is the correct sequence of various stages of operating cycle of a manufacturing company?  1. Raw material conversion period, work-in-progress conversion period, Finished goods conversion period, Receivables conversion period 2. Raw material conversion period, work-in-progress conversion period, Creditors payment period, Receivables conversion period 3. Creditor payment period. Raw material conversion period, Receivables conversion period, work-in- progress conversion period 4. Raw material conversion period, Finished goods conversion period, work-in- progress conversion period. Receivables conversion period 
In this question two quantities are given. Find and compare them and choose the appropriate options. A cylinder of radius R and height H has the same volume as that of a sphere of radius r. The surface area of sphere is more than the curved surface area of cylinder. Quantity I: x, where 9x – 2 = 0 Quantity II: R/H; where a cylinder of radius R and height H has the same volume as that of a sphere of radius r. The surface area of sphere is more than the curved surface area of cylinder.
A simple pendulum has a time period T1, when on the earth’s surface; and T2, when taken to a height R above the earth’s surface (R is the radius of the earth). The value of T2/T1 is?
A simple pendulum is executing simple harmonic motion with a time period T. If the length of the pendulum is increased by 21%, the increase in the time period of the pendulum of increased length is?
The time period of a simple pendulum made by using a thin copper wire of length L is T. Suppose the temperature of the room in which this simple pendulum is placed increases by 30°C. What will be the effect on the time period of the pendulum?
If the amplitude or oscillation of a simple pendulum is very small, then its time period of oscillation
1. depends on the length of the pendulum, L.
2. depends on the acceleration due to gravity, g.
3. depends upon the mass of the bob of the pendulum, m.
4. does not depend upon the amplitude of the pendulum, A.
Select the correct answer: