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Rubidium Chloride (RbCl) has NaCl like structure at normal pressures. If the radius of the Chloride ion is 1.54 Å, what is the unit cell edge length for RbCl? (Assuming anion-anion contact)

Rubidium Chloride (RbCl) has NaCl like structure at normal pressures. If the radius of the Chloride ion is 1.54 Å, what is the unit cell edge length for RbCl? (Assuming anion-anion contact) Correct Answer 4.32 Å

Given, Radius of Chloride ion (r–) = 0.154 nm Distance between the centres of the Chloride ions = 2 x 0.154 = 0.308 nm Let the edge length of cube = a Distance between Rb+ and Cl– ions = a/2 Therefore, the distance between Cl– ions = (2 x (a/2)2)1/2 0.308 = (2 x (a/2)2)1/2 0.094864 = 2 x (a/2)2 0.047432 = (a/2)2 0.218 = (a/2) a = 0.432 nm = 4.32 Å.

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