Find the value of mode if the mean and median are 25 and 20 respectively.

Which of the following are the correct statements with regard to positive skewed distribution? (A) Mean > Media > Mode (B) Mean < Median < Mode (C) Q3 - Median < Median - Q1 (D) Q3 - Median > Median - Q1 (E) Mean = Median = Mod Choose the correct answer from the options given below:

A

(A), (D) only

B

(A), (C) only

C

(B), (C), (D) only

D

(B), (C), (D), (E) only

Consider the statements given below- A: Relationship between Mean, Median and Mode is : Mode = 3 Median – 2 Mean B: It is also possible that there can be more than one mode or no mode for a data set. C: In a data set, half of the data points are smaller than the median and half of the data points are larger. Which of the above statement(s) is/are TRUE?

A

All A, B and C

B

Only A and B

C

Only A and C

D

Only B and C

The maximum weight lifted by 750 participants are recorded and it is found that the Mean and the Median of this distribution are both more than the Mode. If the Mean and the Median are 184 Kg and 178 Kg respectively, then which of the following is the most likely value of the Mode (in kg).

A

168

B

172

C

162

D

166

Which two of the following statements are true? a) Skewness studies the flatness or peakedness of the distribution b) A positively skewed distribution curve is stretched more to the right than to the left c) On the basis of empirical relationship between mean, mode and median for moderately asymmetrical distribution, Karl Pearson's coefficient of skewness can be measured by 3 (Mean -Median) divided by Standard Deviation d) If mean < mode, the distribution is positively skewed Choose the correct option from those below:

A

a) and b)

B

b) and c)

C

c) and d)

D

b) and d)

If Mean is M, Median is Md, Mode is Mo, what is the relation between Mean, Median and Mode?

A

Mo = 3Md - 2M

B

3Mo - 2M = Md

C

2M = 3Mo - Md

D

None of these

hat will be the output of the following R code?

> centre <- function(x, type) {+ switch(type,+ mean = mean(x),+ median = median(x),+ trimmed = mean(x, trim = .1))+ }> x <- rcauchy(10)> centre(x, "mean")

A

0.8760325

B

0.5360891

C

0.6086504

D

gives mean with values depending on rcauchy values

What is the formula for the median of Grouped data? * h b) Median = L + * h c) Median = L + + h d) Median = L * * h

A

Median = L + * h

B

(n / 2 – cf) / f

C

(n / 2 – cf) / f

D

(n / 2 – cf) / f

The mean and median of observation 1 are 21 & 22 respectively. The mean of observation 2 whose median is 21 & mode is the same as observation 1.

A

19

B

20

C

20.5

D

19.5

Mean of an observation is 2 times of mode. If median is 5, what is the average of mode and median of the observation?

A

3

B

4

C

5

D

6

Read the following two statements Assertion (A) and Reason (R) and indicate your answer using the codes given below:
Assertion (A): Median is used as a measure of scale value in method of equal appearing intervals.
Reason (R): In normal distribution mean, median and mode are identical.

A

Both (A) and (R) are true and (R) is the correct explanation of (A)

B

Both (A) and (R) are true but (R) is not the correct explanation of (A)

C

(A) is true, (R) is false

D

(A) is false, (R) is true

Find the value of mode if the mean and median are 25 and 20 respectively.

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