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The current passing through a galvanometer is 30 mA, resistance of the galvanometer is 50 Ω and a shunt is 1 Ω is connected to the galvanometer. What is the maximum current that can be measured by this ammeter?

The current passing through a galvanometer is 30 mA, resistance of the galvanometer is 50 Ω and a shunt is 1 Ω is connected to the galvanometer. What is the maximum current that can be measured by this ammeter? Correct Answer 1.53 A

GiveIg = 30 mA = 0.03 A; S = 1 Ω; G = 50 Ω Required equation ➔ Maximum current (I) = \( \) × Ig I = \( \) × 0.03 I = 51 × 0.03 I = 1.53 A

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