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If (x1 + j y1) = (x2 + j y2), then which of the following is true. Here \(j = \sqrt { - 1} ,x\;\& \;y\) are real numbers.

If (x1 + j y1) = (x2 + j y2), then which of the following is true. Here \(j = \sqrt { - 1} ,x\;\& \;y\) are real numbers. Correct Answer x<sub>1</sub> – j y<sub>1</sub> = x<sub>2</sub> – j y<sub>2</sub>

Given that (x1 + j y1) = (x2 + j y2)

⇒ x1 = x2 and y1 = y2

x1 – j y1 = x2 – j y2

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