A train covered 30% of its distance at the speed of 30 km/hr, 5/7th part of the remaining distance covered at the speed of 50 km/hr, and the rest of the distance covered at the speed of 20 km/hr. What is the train's average speed during the journey if the total distance covered by the train is 1587 km?
A train covered 30% of its distance at the speed of 30 km/hr, 5/7th part of the remaining distance covered at the speed of 50 km/hr, and the rest of the distance covered at the speed of 20 km/hr. What is the train's average speed during the journey if the total distance covered by the train is 1587 km? Correct Answer 100/3 km/hr
Given:
The total distance traveled by train is 1587 km.
30% of distance at the speed of 30 km/hr,
5/7th part of the remaining distance covered by 50 km/hr,
Rest of the distance covered at the speed of 20 km/hr.
Formula Used:
Speed = Distance/Time
Aerage Speed = Total distance traveled/Total time taken
Calculation:
30% = 30/100 = 3/10
Let the total distance be x km
⇒ 3x/10 km travelled by 30km/hr
Time required to travel 3x/10km by 30 km/hr is,
⇒ Time = {3x/10}/30 = 3x/300 = x/100 ----(I)
Remaining distance to travel is,
⇒ x – 3/10(x) = (10 – 3)x/10 = 7x/10
Now 5/7th of remaining part traveled by 50km/hr.
⇒ 5/7 × (7x/10) = x/2
⇒ x/2 km traveled by 50 km/hr
Time required to travel x/2 km by 50 km/hr is,
⇒ Time = {x/2}/50 = x/100 ----(II)
Over all remaining distance is,
⇒ x – (3x/10 + x/2) = x – (8x/10)
⇒ 2x/10 = x/5
⇒ x/5 km distance traveled by 20 km/hr
Time required to travel x/5 km by 20 km/hr is,
⇒ Time = {x/5}/20= x/100 ----(III)
According to the question,
Average speed = x/{x/100 + x/100 + x/100}
⇒ Average speed = x/(3x/100) = 100/3
∴ The average speed of a train is 100/3 km/hr