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A train starts from Panipat at 6:00 a.m. and reaches Pathankot at 10 a.m. The other train starts from Pathankot at 8 a.m. and reaches Panipat at 11:30 a.m. If the distance between Panipat and Pathankot is 28 km, then at what time did the two trains meet each other?

A train starts from Panipat at 6:00 a.m. and reaches Pathankot at 10 a.m. The other train starts from Pathankot at 8 a.m. and reaches Panipat at 11:30 a.m. If the distance between Panipat and Pathankot is 28 km, then at what time did the two trains meet each other? Correct Answer 8:56 am

GIVEN :

Let the distance between Panipat and Pathankot be 28 km

 

CALCULATION :

The Speed of the train starting from Panipat = 28/4 = 7 km/h

The Speed of train starting from Pathankot = 28/3.5 = 8 km/h

Suppose the two trains meet x hours after 6.00 am

Then x × 7 + (x - 2) x 8 = 28

or, 7x + 8x - 16 = 28

or, 15x = 44

or, x = 44/15 = 2h 56 min

Hence, the required time = 8:56 am

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