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What is the sum of the coefficients in the expansion of (3 + 2x)99

What is the sum of the coefficients in the expansion of (3 + 2x)99 Correct Answer 5<sup>99</sup>

Using binomial expansion:

(3 + 2x)99 = a0x0 + a1x1 + a2x2 + a3x3 + ……. + a15x15

After putting x = 1

(3 + 2)99 = a0 + a1 + a2 + a3 + …… + a15

599 = a0 + a1 + a2 + a3 + …… + a15

Hence, required sum = 599

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