In a hotel, 40% had vegetarian lunch while 30% had non-vegetarian lunch and 20% had both type of lunch. If 196 people were present, how many did not eat either type?
In a hotel, 40% had vegetarian lunch while 30% had non-vegetarian lunch and 20% had both type of lunch. If 196 people were present, how many did not eat either type? Correct Answer 98
Given:
Vegetarian lunch = 40%
Non-vegetarian lunch = 30%
Both type lunch = 20%
Total = 196
Concept Used:
x = p + q – r
where, x → Number of persons did not eat either type,
p → People who eat vegetarian lunch,
q → People who eat non-vegetarian lunch
r → People who had both types of lunch
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Calculations:
Number of persons did not eat either type = (40% + 30% – 20%) × 196
⇒ Number of persons who did not eat either type = 98
∴ The number of persons who did not eat either type is 98.