In a hotel, 40% had vegetarian lunch while 30% had non-vegetarian lunch and 20% had both type of lunch. If 196 people were present, how many did not eat either type?

In a hotel, 40% had vegetarian lunch while 30% had non-vegetarian lunch and 20% had both type of lunch. If 196 people were present, how many did not eat either type? Correct Answer 98

Given:

Vegetarian lunch = 40%

Non-vegetarian lunch = 30%

Both type lunch = 20%

Total = 196

Concept Used:

x = p + q – r

where, x → Number of persons did not eat either type,

p → People who eat vegetarian lunch,

q → People who eat non-vegetarian lunch

r → People who had both types of lunch

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Calculations:

Number of persons did not eat either type = (40% + 30% – 20%) × 196

⇒ Number of persons who did not eat either type = 98

∴ The number of persons who did not eat either type is 98.

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