Out of the total number of players, 100/3% are in hotel X and the remaining are in hotel Y. If 20 players from hotel Y are shifted to hotel X, then the number of players in hotel X becomes 50% of the total number of players. If 20 players from hotel X are shifted to hotel Y, then the number of players in hotel X becomes what per cent of the total number of players?
Out of the total number of players, 100/3% are in hotel X and the remaining are in hotel Y. If 20 players from hotel Y are shifted to hotel X, then the number of players in hotel X becomes 50% of the total number of players. If 20 players from hotel X are shifted to hotel Y, then the number of players in hotel X becomes what per cent of the total number of players? Correct Answer 16.67%
Let total players = A
Players in Hotel X = 100/3% of A = A/3
Players in Hotel Y = A - A/3 = 2A/3
According to question:
A/3 + 20 = 50/100 × A
⇒ A/3 + 20 = A/2
⇒ A/2 - A/3 = 20
⇒ A/6 = 20
⇒ A = 20 × 6
⇒ A = 120
Now, Players in Hostel X = 120/3 = 40
Players in Hostel Y = 120 - 40 = 80
Now, if 20 players from hotel X are shifted to hotel Y, then the number of players in hotel X becomes,
= 40 - 20 = 20
And the number of players in hotel X becomes what percent of the total number of players:
20/120 × 100
= 16.67%
Hence, ‘16.67%’ is the correct answer.